完成 yudao-sso-demo-by-code 刷新访问令牌

This commit is contained in:
YunaiV
2022-10-01 20:49:11 +08:00
parent ea71002ed6
commit ff54f16907
6 changed files with 75 additions and 3 deletions

View File

@ -68,6 +68,12 @@ public class OAuth2Client {
return exchange.getBody();
}
/**
* 校验访问令牌,并返回它的基本信息
*
* @param token 访问令牌
* @return 访问令牌的基本信息
*/
public CommonResult<OAuth2CheckTokenRespDTO> checkToken(String token) {
// 1.1 构建请求头
HttpHeaders headers = new HttpHeaders();
@ -88,6 +94,33 @@ public class OAuth2Client {
return exchange.getBody();
}
/**
* 使用刷新令牌,获得(刷新)访问令牌
*
* @param refreshToken 刷新令牌
* @return 访问令牌
*/
public CommonResult<OAuth2AccessTokenRespDTO> refreshToken(String refreshToken) {
// 1.1 构建请求头
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
headers.set("tenant-id", TENANT_ID.toString());
addClientHeader(headers);
// 1.2 构建请求参数
MultiValueMap<String, Object> body = new LinkedMultiValueMap<>();
body.add("grant_type", "refresh_token");
body.add("refresh_token", refreshToken);
// 2. 执行请求
ResponseEntity<CommonResult<OAuth2AccessTokenRespDTO>> exchange = restTemplate.exchange(
BASE_URL + "/token",
HttpMethod.POST,
new HttpEntity<>(body, headers),
new ParameterizedTypeReference<CommonResult<OAuth2AccessTokenRespDTO>>() {}); // 解决 CommonResult 的泛型丢失
Assert.isTrue(exchange.getStatusCode().is2xxSuccessful(), "响应必须是 200 成功");
return exchange.getBody();
}
private static void addClientHeader(HttpHeaders headers) {
// client 拼接,需要 BASE64 编码
String client = CLIENT_ID + ":" + CLIENT_SECRET;

View File

@ -30,4 +30,15 @@ public class AuthController {
return oauth2Client.postAccessToken(code, redirectUri);
}
/**
* 使用刷新令牌,获得(刷新)访问令牌
*
* @param refreshToken 刷新令牌
* @return 访问令牌;注意,实际项目中,最好创建对应的 ResponseVO 类,只返回必要的字段
*/
@PostMapping("/refresh-token")
public CommonResult<OAuth2AccessTokenRespDTO> refreshToken(@RequestParam("refreshToken") String refreshToken) {
return oauth2Client.refreshToken(refreshToken);
}
}