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完成 yudao-sso-demo-by-code 刷新访问令牌
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@ -68,6 +68,12 @@ public class OAuth2Client {
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return exchange.getBody();
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}
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/**
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* 校验访问令牌,并返回它的基本信息
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*
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* @param token 访问令牌
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* @return 访问令牌的基本信息
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*/
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public CommonResult<OAuth2CheckTokenRespDTO> checkToken(String token) {
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// 1.1 构建请求头
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HttpHeaders headers = new HttpHeaders();
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@ -88,6 +94,33 @@ public class OAuth2Client {
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return exchange.getBody();
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}
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/**
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* 使用刷新令牌,获得(刷新)访问令牌
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*
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* @param refreshToken 刷新令牌
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* @return 访问令牌
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*/
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public CommonResult<OAuth2AccessTokenRespDTO> refreshToken(String refreshToken) {
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// 1.1 构建请求头
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HttpHeaders headers = new HttpHeaders();
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headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
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headers.set("tenant-id", TENANT_ID.toString());
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addClientHeader(headers);
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// 1.2 构建请求参数
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MultiValueMap<String, Object> body = new LinkedMultiValueMap<>();
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body.add("grant_type", "refresh_token");
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body.add("refresh_token", refreshToken);
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// 2. 执行请求
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ResponseEntity<CommonResult<OAuth2AccessTokenRespDTO>> exchange = restTemplate.exchange(
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BASE_URL + "/token",
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HttpMethod.POST,
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new HttpEntity<>(body, headers),
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new ParameterizedTypeReference<CommonResult<OAuth2AccessTokenRespDTO>>() {}); // 解决 CommonResult 的泛型丢失
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Assert.isTrue(exchange.getStatusCode().is2xxSuccessful(), "响应必须是 200 成功");
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return exchange.getBody();
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}
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private static void addClientHeader(HttpHeaders headers) {
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// client 拼接,需要 BASE64 编码
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String client = CLIENT_ID + ":" + CLIENT_SECRET;
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@ -30,4 +30,15 @@ public class AuthController {
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return oauth2Client.postAccessToken(code, redirectUri);
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}
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/**
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* 使用刷新令牌,获得(刷新)访问令牌
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*
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* @param refreshToken 刷新令牌
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* @return 访问令牌;注意,实际项目中,最好创建对应的 ResponseVO 类,只返回必要的字段
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*/
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@PostMapping("/refresh-token")
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public CommonResult<OAuth2AccessTokenRespDTO> refreshToken(@RequestParam("refreshToken") String refreshToken) {
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return oauth2Client.refreshToken(refreshToken);
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}
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}
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