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简化 mock login 模拟登录的实现,由 TokenAuthenticationFilter 直接实现
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@ -96,32 +96,6 @@ public class AuthServiceImplTest extends BaseDbUnitTest {
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username); // 异常提示为 username
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}
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@Test
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public void testMockLogin_success() {
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// 准备参数
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Long userId = randomLongId();
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// mock 方法 01
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AdminUserDO user = randomPojo(AdminUserDO.class, o -> o.setId(userId));
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when(userService.getUser(eq(userId))).thenReturn(user);
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// 调用
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LoginUser loginUser = authService.mockLogin(userId);
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// 断言
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AssertUtils.assertPojoEquals(user, loginUser, "updateTime");
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}
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@Test
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public void testMockLogin_userNotFound() {
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// 准备参数
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Long userId = randomLongId();
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// mock 方法
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// 调用, 并断言异常
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assertThrows(UsernameNotFoundException.class, // 抛出 UsernameNotFoundException 异常
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() -> authService.mockLogin(userId),
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String.valueOf(userId)); // 异常提示为 userId
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}
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@Test
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public void testLogin_captchaNotFound() {
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// 准备参数
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