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review 拼团、秒杀活动的实现
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@ -70,6 +70,7 @@ public class LocalDateTimeUtils {
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* @param endTime2 校验所需的结束时间
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* @return 是否重叠
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*/
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// TODO @puhui999:LocalDateTimeUtil.isOverlap() 是不是可以满足呀?
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public static boolean checkTimeOverlap(LocalTime startTime1, LocalTime endTime1, LocalTime startTime2, LocalTime endTime2) {
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// 判断时间是否重叠
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// 开始时间在已配置时段的结束时间之前 且 结束时间在已配置时段的开始时间之后 []
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