营销活动:完善 review 提到的问题

This commit is contained in:
puhui999
2023-10-23 12:02:13 +08:00
parent ec27a1bae5
commit 6723cae781
17 changed files with 130 additions and 109 deletions

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@ -12,8 +12,7 @@ import cn.iocoder.yudao.module.member.dal.dataobject.signin.MemberSignInRecordDO
import org.mapstruct.Mapper;
import org.mapstruct.factory.Mappers;
import java.time.LocalDateTime;
import java.time.temporal.ChronoUnit;
import java.util.Comparator;
import java.util.List;
import java.util.Map;
@ -44,31 +43,33 @@ public interface MemberSignInRecordConvert {
AppMemberSignInRecordRespVO coverRecordToAppRecordVo(MemberSignInRecordDO memberSignInRecordDO);
default MemberSignInRecordDO convert(Long userId, MemberSignInRecordDO firstRecord, List<MemberSignInConfigDO> signInConfigs) {
// 1. 计算今天是第几天签到
long day = ChronoUnit.DAYS.between(firstRecord.getCreateTime(), LocalDateTime.now());
// 2. 初始化签到信息
// TODO @puhui999signInRecord=》record
MemberSignInRecordDO signInRecord = new MemberSignInRecordDO().setUserId(userId)
.setDay(Integer.parseInt(Long.toString(day))) // 设置签到天数 TODO @puhui999day 应该跟着第几天签到走;不是累加哈;另外 long 转 int应该 (int) day 就可以了。。。
.setPoint(0) // 设置签到积分默认为
default MemberSignInRecordDO convert(Long userId, MemberSignInRecordDO lastRecord, List<MemberSignInConfigDO> signInConfigs) {
// 1. 获取最大签到天数积分配置
signInConfigs.sort(Comparator.comparing(MemberSignInConfigDO::getDay));
MemberSignInConfigDO lastConfig = signInConfigs.get(signInConfigs.size() - 1); // 最大签到天数配置
// 1.2. 计算今天是第几天签到
int day = 1;
if (lastRecord != null) {
day = lastRecord.getDay() + 1;
}
// 1.3 判断是否超出了最大签到配置
if (day > lastConfig.getDay()) {
day = 1; // 超过最大配置的天数,重置到第一天。(也就是说开启下一轮签到)
}
// 1.4 初始化签到信息
MemberSignInRecordDO record = new MemberSignInRecordDO().setUserId(userId)
.setDay(day) // 设置签到天数
.setPoint(0) // 设置签到积分默认为 0
.setExperience(0); // 设置签到经验默认为 0
// 3. 获取签到对应的积分数
MemberSignInConfigDO lastConfig = signInConfigs.get(signInConfigs.size() - 1); // 最大签到天数
if (day > lastConfig.getDay()) { // 超出范围按第一天的经验计算
// TODO @puhui999不能直接取 0万一它 day 不匹配哈。就是第一天没奖励。。。
signInRecord.setPoint(signInConfigs.get(0).getPoint());
signInRecord.setExperience(signInConfigs.get(0).getExperience());
return signInRecord;
// 2. 获取签到对应的积分
MemberSignInConfigDO config = CollUtil.findOne(signInConfigs, item -> ObjUtil.equal(item.getDay(), record.getDay()));
if (config == null) {
return record;
}
// TODO @puhui999signInConfig 可以改成 config
MemberSignInConfigDO signInConfig = CollUtil.findOne(signInConfigs, config -> ObjUtil.equal(config.getDay(), day));
if (signInConfig == null) {
return signInRecord;
}
signInRecord.setPoint(signInConfig.getPoint());
signInRecord.setExperience(signInConfig.getExperience());
return signInRecord;
record.setPoint(config.getPoint());
record.setExperience(config.getExperience());
return record;
}
}

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@ -35,50 +35,31 @@ public interface MemberSignInRecordMapper extends BaseMapperX<MemberSignInRecord
.orderByDesc(MemberSignInRecordDO::getId));
}
// TODO @puhui999这 2 个方法,是不是一个 first一个 last 就可以了。。
/**
* 获取用户最近的签到记录信息,根据签到时间倒序
*
* @param userId 用户编号
* @return 签到记录列表
*/
default MemberSignInRecordDO selectLastRecordByUserIdDesc(Long userId) {
default MemberSignInRecordDO selectLastRecordByUserId(Long userId) {
return selectOne(new QueryWrapper<MemberSignInRecordDO>()
.eq("user_id", userId)
.orderByDesc("create_time")
.last("limit 1"));
}
/**
* 获取用户最早的签到记录信息,根据签到时间倒序
*
* @param userId 用户编号
* @return 签到记录列表
*/
default MemberSignInRecordDO selectLastRecordByUserIdAsc(Long userId) {
return selectOne(new QueryWrapper<MemberSignInRecordDO>()
.eq("user_id", userId)
.orderByAsc("create_time")
.last("limit 1"));
}
default Long selectCountByUserId(Long userId) {
// TODO @puhui999可以使用 selectCount 里面允许传递字段的方法
return selectCount(new LambdaQueryWrapperX<MemberSignInRecordDO>()
.eq(MemberSignInRecordDO::getUserId, userId));
return selectCount(MemberSignInRecordDO::getUserId, userId);
}
/**
* 获取用户的签到记录列表信息,根据签到时间倒序
* 获取用户的签到记录列表信息
*
* @param userId 用户编号
* @return 签到记录信息
*/
// TODO @puhui999这个排序可以交给 service 哈;
default List<MemberSignInRecordDO> selectListByUserId(Long userId) {
return selectList(new LambdaQueryWrapperX<MemberSignInRecordDO>()
.eq(MemberSignInRecordDO::getUserId, userId)
.orderByDesc(MemberSignInRecordDO::getCreateTime));
return selectList(MemberSignInRecordDO::getUserId, userId);
}
}

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@ -58,36 +58,37 @@ public class MemberSignInRecordServiceImpl implements MemberSignInRecordService
@Override
public AppMemberSignInRecordSummaryRespVO getSignInRecordSummary(Long userId) {
// 1. 初始化默认返回信息
// TODO @puhui999这里 vo 改成 summary 会更好理解;
AppMemberSignInRecordSummaryRespVO vo = new AppMemberSignInRecordSummaryRespVO();
vo.setTotalDay(0);
vo.setContinuousDay(0);
vo.setTodaySignIn(false);
AppMemberSignInRecordSummaryRespVO summary = new AppMemberSignInRecordSummaryRespVO();
summary.setTotalDay(0);
summary.setContinuousDay(0);
summary.setTodaySignIn(false);
// 2. 获取用户签到的记录数
Long signCount = signInRecordMapper.selectCountByUserId(userId);
if (ObjUtil.equal(signCount, 0L)) {
return vo;
return summary;
}
vo.setTotalDay(signCount.intValue()); // 设置总签到天数
summary.setTotalDay(signCount.intValue()); // 设置总签到天数
// 3. 校验当天是否有签到
// TODO @puhui999是不是 signInRecord 可以精简成 record 哈另外Desc 貌似可以去掉哈;最后一条了;
MemberSignInRecordDO signInRecord = signInRecordMapper.selectLastRecordByUserIdDesc(userId);
if (signInRecord == null) {
return vo;
MemberSignInRecordDO lastRecord = signInRecordMapper.selectLastRecordByUserId(userId);
if (lastRecord == null) {
return summary;
}
vo.setTodaySignIn(DateUtils.isToday(signInRecord.getCreateTime()));
summary.setTodaySignIn(DateUtils.isToday(lastRecord.getCreateTime()));
// 4. 校验今天是否签到,没有签到则直接返回
if (!vo.getTodaySignIn()) {
return vo;
if (!summary.getTodaySignIn()) {
return summary;
}
// 4.1. 判断连续签到天数
// TODO @puhui999连续签到可以基于 signInRecord 的 day 和当前时间判断呀?
// TODO @puhui999连续签到可以基于 lastRecord 的 day 和当前时间判断呀?按 day 统计连续签到天数可能不准确
// 1. day 只是记录第几天签到的有可能不连续,比如第一次签到是周一,第二次签到是周三这样 lastRecord 的 day 为 2 但是并不是连续的两天
// 2. day 超出签到规则的最大天数会重置到从第一天开始签到(我理解为开始下一轮,类似一周签到七天七天结束下周又从周一开始签到)
List<MemberSignInRecordDO> signInRecords = signInRecordMapper.selectListByUserId(userId);
vo.setContinuousDay(calculateConsecutiveDays(signInRecords));
return vo;
signInRecords.sort(Comparator.comparing(MemberSignInRecordDO::getCreateTime).reversed()); // 根据签到时间倒序
summary.setContinuousDay(calculateConsecutiveDays(signInRecords));
return summary;
}
/**
@ -144,17 +145,14 @@ public class MemberSignInRecordServiceImpl implements MemberSignInRecordService
@Transactional(rollbackFor = Exception.class)
public MemberSignInRecordDO createSignRecord(Long userId) {
// 1. 获取当前用户最近的签到
MemberSignInRecordDO lastRecord = signInRecordMapper.selectLastRecordByUserIdDesc(userId);
MemberSignInRecordDO lastRecord = signInRecordMapper.selectLastRecordByUserId(userId);
// 1.1. 判断是否重复签到
validateSigned(lastRecord);
// 2. 获取当前用户最早的一次前端记录,用于计算今天是第几天签到
MemberSignInRecordDO firstRecord = signInRecordMapper.selectLastRecordByUserIdAsc(userId);
// 2.1. 获取所有的签到规则
List<MemberSignInConfigDO> signInConfigs = signInConfigService.getSignInConfigList(CommonStatusEnum.ENABLE.getStatus());
signInConfigs.sort(Comparator.comparing(MemberSignInConfigDO::getDay));
// 2.2. 组合数据
MemberSignInRecordDO record = MemberSignInRecordConvert.INSTANCE.convert(userId, firstRecord, signInConfigs);
MemberSignInRecordDO record = MemberSignInRecordConvert.INSTANCE.convert(userId, lastRecord, signInConfigs);
// 3. 插入签到记录
signInRecordMapper.insert(record);