code review:拼团逻辑

This commit is contained in:
YunaiV
2023-10-16 09:07:02 +08:00
parent 7bc3b7b2ff
commit 4359c584bb
8 changed files with 16 additions and 16 deletions

View File

@@ -40,8 +40,6 @@ public class CombinationRecordController {
@Lazy
private CombinationRecordService combinationRecordService;
// 然后如果 headId 非空,并且第一页,单独多查询一条 head ;放到第 0 个位置;相当于说,第一页特殊一点;
@GetMapping("/page")
@Operation(summary = "获得拼团记录分页")
@PreAuthorize("@ss.hasPermission('promotion:combination-record:query')")

View File

@@ -47,13 +47,13 @@ public class AppCombinationRecordController {
public CommonResult<AppCombinationRecordSummaryRespVO> getCombinationRecordSummary() {
AppCombinationRecordSummaryRespVO summary = new AppCombinationRecordSummaryRespVO();
// 1. 获得拼团参与用户数量
Long count = combinationRecordService.getCombinationUserCount();
if (count == 0) {
Long userCount = combinationRecordService.getCombinationUserCount();
if (userCount == 0) {
summary.setAvatars(Collections.emptyList());
summary.setUserCount(count);
summary.setUserCount(userCount);
return success(summary);
}
summary.setUserCount(count);
summary.setUserCount(userCount);
// 2. 获得拼团记录头像
List<CombinationRecordDO> records = combinationRecordService.getLatestCombinationRecordList(

View File

@@ -192,7 +192,6 @@ public interface CombinationActivityConvert {
return result;
}
default AppCombinationRecordDetailRespVO convert(Long userId, CombinationRecordDO headRecord, List<CombinationRecordDO> memberRecords) {
AppCombinationRecordDetailRespVO respVO = new AppCombinationRecordDetailRespVO()
.setHeadRecord(convert(headRecord)).setMemberRecords(convertList3(memberRecords));

View File

@@ -99,10 +99,10 @@ public interface CombinationRecordMapper extends BaseMapperX<CombinationRecordDO
LambdaQueryWrapperX<CombinationRecordDO> queryWrapper = new LambdaQueryWrapperX<CombinationRecordDO>()
.eqIfPresent(CombinationRecordDO::getStatus, pageVO.getStatus())
.betweenIfPresent(CombinationRecordDO::getCreateTime, pageVO.getCreateTime());
// 如果 headId 非空,说明查询指定团的团长 + 团员的拼团记录
if (pageVO.getHeadId() != null) {
queryWrapper.eq(CombinationRecordDO::getId, pageVO.getHeadId())
.or()
.eq(CombinationRecordDO::getHeadId, pageVO.getHeadId());
queryWrapper.eq(CombinationRecordDO::getId, pageVO.getHeadId()) // 团长
.or().eq(CombinationRecordDO::getHeadId, pageVO.getHeadId()); // 团员
}
return selectPage(pageVO, queryWrapper);
}
@@ -127,6 +127,7 @@ public interface CombinationRecordMapper extends BaseMapperX<CombinationRecordDO
*
* @return 参加过拼团的用户数
*/
// TODO @puhui9991方法名直接 selectUserCount2COUNT(DISTINCT(user_id)) 就可以啦,不用 group by 哈
default Long selectUserDistinctCount() {
return selectCount(new QueryWrapper<CombinationRecordDO>()
.select("DISTINCT (user_id)")

View File

@@ -339,19 +339,20 @@ public class CombinationRecordServiceImpl implements CombinationRecordService {
@Override
public KeyValue<Integer, Integer> expireCombinationRecord() {
// 1.获取所有正在进行中的过期的父拼团
// 1. 获取所有正在进行中的过期的父拼团
List<CombinationRecordDO> headExpireRecords = combinationRecordMapper.selectListByHeadIdAndStatusAndExpireTimeLt(
CombinationRecordDO.HEAD_ID_GROUP, CombinationRecordStatusEnum.IN_PROGRESS.getStatus(), LocalDateTime.now());
if (CollUtil.isEmpty(headExpireRecords)) {
return new KeyValue<>(0, 0);
}
// 2.获取拼团活动
// 2. 获取拼团活动
List<CombinationActivityDO> activities = combinationActivityService.getCombinationActivityListByIds(
convertSet(headExpireRecords, CombinationRecordDO::getActivityId));
Map<Long, CombinationActivityDO> activityMap = convertMap(activities, CombinationActivityDO::getId);
// 3.校验是否虚拟成团
// TODO @puhui999这里可以改成“每个团”处理一次哈这样 handleExpireRecord、handleVirtualGroupRecord 都改成按团处理,每个是一个小事务;
// 3. 校验是否虚拟成团
List<CombinationRecordDO> virtualGroupHeadRecords = new ArrayList<>(); // 虚拟成团
for (Iterator<CombinationRecordDO> iterator = headExpireRecords.iterator(); iterator.hasNext(); ) {
CombinationRecordDO record = iterator.next();