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code review:签到逻辑
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@ -48,19 +48,20 @@ public interface MemberSignInRecordConvert {
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// 1. 计算今天是第几天签到
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long day = ChronoUnit.DAYS.between(firstRecord.getCreateTime(), LocalDateTime.now());
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// 2. 初始化签到信息
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// TODO @puhui999:signInRecord=》record
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MemberSignInRecordDO signInRecord = new MemberSignInRecordDO().setUserId(userId)
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.setDay(Integer.parseInt(Long.toString(day))) // 设置签到天数
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.setPoint(0) // 设置签到积分默认为 0
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.setDay(Integer.parseInt(Long.toString(day))) // 设置签到天数 TODO @puhui999:day 应该跟着第几天签到走;不是累加哈;另外 long 转 int,应该 (int) day 就可以了。。。
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.setPoint(0) // 设置签到积分默认为
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.setExperience(0); // 设置签到经验默认为 0
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// 3. 获取签到对应的积分数
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MemberSignInConfigDO lastConfig = signInConfigs.get(signInConfigs.size() - 1); // 最大签到天数
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if (day > lastConfig.getDay()) { // 超出范围按第一天的经验计算
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// TODO @puhui999:不能直接取 0,万一它 day 不匹配哈。就是第一天没奖励。。。
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signInRecord.setPoint(signInConfigs.get(0).getPoint());
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signInRecord.setExperience(signInConfigs.get(0).getExperience());
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return signInRecord;
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}
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// TODO @puhui999:signInConfig 可以改成 config;
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MemberSignInConfigDO signInConfig = CollUtil.findOne(signInConfigs, config -> ObjUtil.equal(config.getDay(), day));
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if (signInConfig == null) {
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return signInRecord;
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@ -35,9 +35,9 @@ public interface MemberSignInRecordMapper extends BaseMapperX<MemberSignInRecord
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.orderByDesc(MemberSignInRecordDO::getId));
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}
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// TODO @puhui999:这 2 个方法,是不是一个 first;一个 last 就可以了。。
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/**
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* 获取用户最近的签到记录信息,根据签到时间倒序
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* 获取用户最近的签到记录信息,根据签到时间倒序
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*
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* @param userId 用户编号
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* @return 签到记录列表
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@ -63,6 +63,7 @@ public interface MemberSignInRecordMapper extends BaseMapperX<MemberSignInRecord
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}
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default Long selectCountByUserId(Long userId) {
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// TODO @puhui999:可以使用 selectCount 里面允许传递字段的方法
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return selectCount(new LambdaQueryWrapperX<MemberSignInRecordDO>()
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.eq(MemberSignInRecordDO::getUserId, userId));
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}
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@ -73,6 +74,7 @@ public interface MemberSignInRecordMapper extends BaseMapperX<MemberSignInRecord
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* @param userId 用户编号
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* @return 签到记录信息
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*/
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// TODO @puhui999:这个排序,可以交给 service 哈;
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default List<MemberSignInRecordDO> selectListByUserId(Long userId) {
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return selectList(new LambdaQueryWrapperX<MemberSignInRecordDO>()
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.eq(MemberSignInRecordDO::getUserId, userId)
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@ -58,6 +58,7 @@ public class MemberSignInRecordServiceImpl implements MemberSignInRecordService
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@Override
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public AppMemberSignInRecordSummaryRespVO getSignInRecordSummary(Long userId) {
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// 1. 初始化默认返回信息
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// TODO @puhui999:这里 vo 改成 summary 会更好理解;
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AppMemberSignInRecordSummaryRespVO vo = new AppMemberSignInRecordSummaryRespVO();
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vo.setTotalDay(0);
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vo.setContinuousDay(0);
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@ -71,6 +72,7 @@ public class MemberSignInRecordServiceImpl implements MemberSignInRecordService
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vo.setTotalDay(signCount.intValue()); // 设置总签到天数
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// 3. 校验当天是否有签到
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// TODO @puhui999:是不是 signInRecord 可以精简成 record 哈;另外,Desc 貌似可以去掉哈;最后一条了;
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MemberSignInRecordDO signInRecord = signInRecordMapper.selectLastRecordByUserIdDesc(userId);
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if (signInRecord == null) {
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return vo;
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@ -82,6 +84,7 @@ public class MemberSignInRecordServiceImpl implements MemberSignInRecordService
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return vo;
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}
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// 4.1. 判断连续签到天数
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// TODO @puhui999:连续签到,可以基于 signInRecord 的 day 和当前时间判断呀?
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List<MemberSignInRecordDO> signInRecords = signInRecordMapper.selectListByUserId(userId);
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vo.setContinuousDay(calculateConsecutiveDays(signInRecords));
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return vo;
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@ -164,7 +167,6 @@ public class MemberSignInRecordServiceImpl implements MemberSignInRecordService
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if (!ObjectUtils.equalsAny(record.getExperience(), null, 0)) {
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memberLevelService.addExperience(userId, record.getExperience(), MemberExperienceBizTypeEnum.SIGN_IN, String.valueOf(record.getId()));
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}
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return record;
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}
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